tijian_tieying/web/Common/DistanceHelper.cs
2025-02-20 12:14:39 +08:00

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using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace ZWL.Common
{
public static class DistanceHelper
{
/// <summary>
/// 根据一个给定经纬度的点和距离,进行附近地点查询
/// </summary>
/// <param name="longitude">经度</param>
/// <param name="latitude">纬度</param>
/// <param name="distance">距离(单位:公里或千米)</param>
/// <returns>返回一个范围的4个点最小纬度和纬度最大经度和纬度</returns>
public static Boolean FindNeighPosition(double yhJd,double hyWd,double longitude, double latitude, double distance)
{
//先计算查询点的经纬度范围
double r = 6378.137;//地球半径千米
double dis = distance;//千米距离
double dlng = 2 * Math.Asin(Math.Sin(dis / (2 * r)) / Math.Cos(latitude * Math.PI / 180));
dlng = dlng * 180 / Math.PI;//角度转为弧度
double dlat = dis / r;
dlat = dlat * 180 / Math.PI;
double minlat = latitude - dlat;
double maxlat = latitude + dlat;
double minlng = longitude - dlng;
double maxlng = longitude + dlng;
/*new PositionModel
{
MinLat = minlat,
MaxLat = maxlat,
MinLng = minlng,
MaxLng = maxlng
};*/
if (minlng < yhJd && yhJd < maxlng && minlat < hyWd && hyWd < maxlat)
{
return true;
}
return false;
}
/// <summary>
/// 计算两点位置的距离,返回两点的距离,单位:公里或千米
/// 该公式为GOOGLE提供误差小于0.2米
/// </summary>
/// <param name="lat1">第一点纬度</param>
/// <param name="lng1">第一点经度</param>
/// <param name="lat2">第二点纬度</param>
/// <param name="lng2">第二点经度</param>
/// <returns>返回两点的距离,单位:公里或千米</returns>
public static double GetDistance(double lat1, double lng1, double lat2, double lng2)
{
//地球半径,单位米
double EARTH_RADIUS = 6378137;
double radLat1 = Rad(lat1);
double radLng1 = Rad(lng1);
double radLat2 = Rad(lat2);
double radLng2 = Rad(lng2);
double a = radLat1 - radLat2;
double b = radLng1 - radLng2;
double result = 2 * Math.Asin(Math.Sqrt(Math.Pow(Math.Sin(a / 2), 2) + Math.Cos(radLat1) * Math.Cos(radLat2) * Math.Pow(Math.Sin(b / 2), 2))) * EARTH_RADIUS;
return result / 1000;
}
/// <summary>
/// 经纬度转化成弧度
/// </summary>
/// <param name="d"></param>
/// <returns></returns>
private static double Rad(double d)
{
return (double)d * Math.PI / 180d;
}
}
}